Judd's Observation  (or Judd's Relation)
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	I thought of this while sitting around in my very first apartment,
at the beginning of my sophmore year of college.

	Note that

	1^3 + 2^3 	= (1+2)^2
	1^3 + 2^3 + 3^3 = (1+2+3)^2

And it is easy to show that, in general,

	1^3 + 2^3 + ... + n^3 = (1+2+...+n)^2 = [ n(n+1)/2 ]^2

oooooOOOOOOoooooohhhh!  aaaAAAAAAAAAAAaaaaaahhhhh!